Question

cos58°/sin32° + sin22°/cos68° - cos38°cosec52°/tan18°tan35°tan60°tan72°tan55°​

Answer 1

Answer:-Cos 58 can written as cos(90-32)=sin 32-----equation1st

And sin 22 can be written as sin(90-68)=Cos68---equation 2nd

Therefore,Cos58/sin32+sin22/Cos68

From equation 1st and 2nd

Sin 32/sin32+Cos68/Cos68

=1+1=2

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Answer 2

Answer:

Step-by-step explanation:

cos(A) = sin(90-A)

cos58=sin(90-58) = sin(32)

cos68= sin(90-68)= sin22

So cos58°/sin32°  = cos58°/ cos58° = 1

sin22°/cos68°= cos68°/cos68° =1

cos38°cosec52=cos38°/sin52°= cos38°/sin(90°-38°) = cos38°/cos38°=1

tan(90-A) = cotA=1/tanA

tan18°tan35°tan60°tan72°tan55°​ = tan18°tan72°tan35°tan55°tan60°

(tan18°/tan18°)(tan35°/tan35°)(tan60°) = tan60°

cos58°/sin32° + sin22°/cos68° - cos38°cosec52°/tan18°tan35°tan60°tan72°tan55°

=1+1-1/tan60°=2 - 1/√3