Question

The taxi fare in a city is as follows: For the first kilometre, the fare is Rs. 8 and for the subsequent distance it is Rs. 5 per km. Talking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw it's graph.​

Answer 1

Answer:

IMPORTANT IN THE QUESTION ARE FOLLOWING

the first kilometre, the fare is Rs. 8

the subsequent distance it is Rs. 5 per km.

the distance covered as x km

THEN TOTAL FARE IS RS Y

THEN TOTAL DISTANCE COVERED = X KM

FARE FOR 1ST KM =RS  8

FARE FOR THE REST OF THE DISTANCE = RS 5 * REMANING DISTANCE

                                                                           =  RS 5(X-1)

TOTAL FARE = FARE FOR 1ST KM  + FARE FOR REST (X-1)

         Y = 8+5X-5

         Y = 5X+3

Step-by-step explanation:

HOPE ITS HEP YOU

THANK YOU

IF THIS ANSWER HELP YOU PLEASE MARK AS BRILLIENT

Answer 2

:

Mark Me As Brainliest And Thank Me If The Answer Is Useful.

-- :

x 0  1 2

y 3 8  13

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3    ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)