Question

cos60°/cos^245° -3 tan30°+5cos90°plss answer​ I will mark it as a brainliest

Answer 1

Answer:

cos60°/cos.^2(45°)-3tan30°+5cos 90°

=(1/2)/(1/√2)^2-3(1/√3)+5(0)

=1-3/√3+0

=√3-3/√3

on multiplying by √3 in numerator and denominator, we get

=√3(√3-3)/√3(√3)

=(3-3√3)/3

=3(1-√3)/3

=1-√3

that's your answer