Math, asked by sanayamalik65, 11 months ago

cos63°/sin27° + tan35°/sin35° - cosec55°/tan45°​

Answers

Answered by adityaaditya50128
7

Answer:

1

Step-by-step explanation:

cos63/sin27 + tan35/sin35 - cosec55/tan45

co63/sin(90-63) + sin35/cos35 × sin35 - cosec55 × 1                   (tan45 = 1)

cos63/cos63 + 1/cos35 - cosec55                                      [sin(90-∅) = cos∅]

1+sec35 - cosec(90-35)

1+sec35-sec35                                                                [cosec(90-∅) = sec∅]

= 1

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