Math, asked by BhoomiSutail, 11 months ago

cos63°/sin27°+tan35°/sin35°-cosec55°tan45°

Answers

Answered by streetburner

1

Answer:

1

Step-by-step explanation:

cos63°/sin27°+tan35°/sin35°-cosec55°tan45°

= sin27°/sin27° + sec35° - cosec55°tan45°

= 1 + sec35° - tan45°/sin55°

= 1 + sec35°- 1/cos35°

= 1

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