Question

The sum of three consecutive multiples of 11 is 363 . Find these multiples.
​

Answer 1

Answer:

The sum of three consecutive multiples of 11 is 363 . Find these multiples.

Calculate the formula unit of Kc1 , Naco3 ( atomic mass of k-39ce , CI-35.5U, Na-23u, C-12u, O-16u.

■dont spam the question■

Answer 2

Answer:

If x is a multiple of 11,the next multiple is x+11.

The next to this is x+11+11 or x+22.

So we can take three consecutive multiples of 11 as x, x+11 & x+22

As per the Question,

$x + (x + 11) + (x + 22) = 363$

$=> x + x + 11 + x + 22 = 363$

$= > 3x + 33 = 363$

$= > 3x = 363 - 33$

$= > 3x = 330$

$= > x = \frac{330 }{3} = 110$

Hence, The three consecutive multiples are : 110,121,132.