Question

cos68+ tan
76 in terms of the angles between 0° and 45°

Answer 1

sin(22) + cot(14) by using 90-theta

Answer 2

cot68° + tan76°


Splitting 68° and 76° in two degrees in which one must be 90° respectively.

68° = 90° - 22°

76° = 90° - 14°


So, we can write cos68° as cos( 90 - 22 )° and tan76° as tan( 90 - 14 )°


cos( 90 - 22 )° + tan( 90 - 14 )°



From the properties of trigonometry, we know that cos( 90 - ∅ ) is equal to sin∅ and tan( 90 - ∅ ) is equal to cot∅.

So,



cos( 90 - 22 )° + tan( 90 - 14 )°

sin22° + cot14°



Thus,
cos68° + tan76° in terms of the angles between 0° and 45° is sin22° + cot14°
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