Question

cos70/sin20+cos55.cosec35/tan5.tan25.tan45.tan65.tan85​

Answer 1

Answer:

hope it will help you:-)

Answer 2

Answer: 2

Step-by-step explanation:

(cos 70/ sin 20) + (cos 55 × cosec 35) / (tan 5× tan 25× tan 45 × tan 65× tan 85)

Since, cos A = sin ( 90° - A)

tan A = cot (90° - A)

sec A = cosec ( 90° - A)

tan 45° = 1

= {sin(90°-70°)}/ ( sin 20°) + {cos 55°× sec(90°- 35°)} / {tan 5°× tan 25° × tan 45° × cot (90°-65°) × tan ( 90° - 85°)}

= (sin 20°)/(sin 20°) + { cos 55° × sec 55°} / { tan 5° × tan 25° × tan 45° × cot 25° × cot 5°}

= (sin 20°)/(sin 20°) + { cos 55° × 1/cos 55°} / { tan 5° × tan 25° × tan 45° × 1/tan 25° × 1/tan 5° }

= 1 + (1)/(1)

= 2

Hence the required answer = 2