Question

If two tuning forks a and b are sounded together, they produce 4 beats per second. A is then slightly loaded with wax, they produce beats when sounded again. The frequency of a is 256 hz. The frequency of b will be :

Answer 1

IT WILL BE SAME

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Answer 2

Hi!!!!!!!!

Your answer will be 252 Hz.

First of all your question is wrong.....

Correct question is...

Q - The two tuning forks A and B sounded together produce 4 beats/sec. Then A is slightly loaded and sounded again with B, they produce 2 beats/sec. The frequency of A is 256 Hz. The frequency of B will be?

Now , Your solution step by step is....

nA = Known frequency = 256 Hz, nB = ?

x = 4 bps, which is decreasing after loading (i.e. x↓) also known tuning fork is loaded so nA↓

Hence nA↓ – nB = x↓ ... (i) → Correct cocept

(nB – nA↓ = x↓ ... (ii) → Wrong concept)

⇒ nB = nA – x = 256 – 4 = 252 Hz.(answer)

Hope you got the answer..

Pleased to help you.