Question

Let sin(a+b)=(3^1/2)/2 and cosb=(3^1/2)/2 where a,b are acute angles.What is tan(2a-b) equal to?

Answer 1

Answer: tan(2a-b)=(3^1/2)/3

Step-by-step explanation:

a,b < 90°

sin(a+b)=(3^1/2)/2 -> a+b=60°

cosb = (3^1/2)/2 -> b=30°, a=30°

tan(2a-b)=tan(30°)=(3^1/2)/3