Math, asked by ucvindhrajusonu, 1 year ago

Cos70 / sin20 + cos55 cosec35 / tan5 tan25 tan45 tan65 tan85

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Answered by jahnavimanda
421
(Cos70 / sin20 )+ ((cos55 cosec35 )/ (tan5 tan25 tan45 tan65 tan85))
=(cos(90-20) /sin20)+(cos55 cosec35)/(tan5 tan25 tan45 tan(90-25) tan(90-5))
= (sin20/ sin20) + (
cos55 cosec35)/ (tan5 tan25 tan45 cot25 cot5)
= 1+ (cos55 cosec35)/(1)
= 1+ (cos55/sin35)
= 1+(sin(90-35)/sin35)
= 1+(sin35/sin35)
= 1+1
= 2
Answered by tejaskhemka19
66

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