Question

cos70/sin20+cos55×cosec35/tan5× tan25×tan85×tan65=2​

Answer 1

$\huge\red{Heya\: Mate}$.....

(Cos70 / sin20 )+ ((cos55 cosec35 )/ (tan5 tan25 tan45 tan65 tan85))

=(cos(90-20) /sin20)+(cos55 cosec35)/(tan5 tan25 tan45 tan(90-25) tan(90-5))

= (sin20/ sin20) + (cos55 cosec35)/ (tan5 tan25 tan45 cot25 cot5)

= 1+ (cos55 cosec35)/(1)

= 1+ (cos55/sin35)

= 1+(sin(90-35)/sin35)

= 1+(sin35/sin35)

= 1+1

= 2

HOPE IT WILL HELP YOU.....