Math, asked by san91, 1 year ago

cos75/sin15+sin12/cos78-cos18•cosec72

Answers

Answered by Swarup1998
52
◀ HERE'S ⏬ YOUR ANSWER▶

 \frac{cos75}{sin15}  +  \frac{sin12}{cos78}  - cos18.cosec72 \\  =  \frac{cos(90 - 15)}{sin15}  +  \frac{sin(90 - 78)}{cos78}  - cos(90 - 72).cosec72 \\  =  \frac{sin15}{sin15}  +  \frac{cos78}{cos78}  - sin72.cosec72 \\  = 1 + 1 - 1 \\  = 1

⏏HOPE THIS ⬆ HELPS YOU⏏

san91: thanks
Swarup1998: You are welcome.
Answered by sirisailaja1
9

hope this helps you mark as brainlist

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