Cos80°/sin10°+cos59°cosec31°=?
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Answer:
{sinΦ=cos (90-Φ)
cosecΦ= 1/sinΦ}
cos 80°/sin 10°+ cos 59°cosec31°
cos 80/ cos (90-10) +cos 59/sin31
cos 80/cos80 + cos 59/cos (90-59)
1+cos59/cos59
1+1
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Step-by-step explanation:
its yur solution dear.....
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