Math, asked by satwikmohanty5580, 9 months ago

Cos80°/sin10°+cos59°cosec31°=?

Answers

Answered by Anonymous
0

Answer:

{sinΦ=cos (90-Φ)

cosecΦ= 1/sinΦ}

cos 80°/sin 10°+ cos 59°cosec31°

cos 80/ cos (90-10) +cos 59/sin31

cos 80/cos80 + cos 59/cos (90-59)

1+cos59/cos59

1+1

2

Answered by ritvik86
0

Step-by-step explanation:

its yur solution dear.....

Attachments:
Similar questions