Math, asked by anchal566, 1 year ago

Cos8a cos5a - cos12a cos9a /sin8a cos5a + cos12a sin9a = tan 4a

Answers

Answered by Anonymous
3

(cos8A.cos5A-cos12A.cos9A)/(sin8A.cos5A+cos12A.sin9A)

=> [1/2 {cos13A+cos3A}-1/2 {cos21A+cos3A}]/[1/2 {sin13A+sin3A}+1/2 {sin21A-sin3A}]

=>( cos13A-cos21A)/(sin13A+sin21A)

=> 2sin17A.sin4A/2sin17A.cos4A

=> tan4A

Similar questions