Question

cosA/1+sinA+1+sinA/cosA=2secA​

Answer 1

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Answer 2

LHS: cos a/1+sin A + 1+sin A/cos A

cos A(cos A) +(1+sin A)(1+sin A)/(1+sin A) cos A

(cos ^A+ sin ^ A + 1+ 2 sin A)/(1+ sin A) cos A

2(1+1 sin A)/cos A ( 1+ sin A)

2/ cos A

2 sec A.

LHS = RHS. (proved)

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