Question

CosA /1-SinA +SinA /1-Sin A =SinA Cos A/( 1-sinA) (1-Cos A)​

Answer 1

Here is ur answer:

=LHS

= cosA/(1-sinA) + sinA/(1-cosA) +1

= [cosA(1-cosA)+sinA(1-sinS)+(1-sinA) (1-cosA)]/(1-sinA) (1-cisA)

=(cosA-cos²A+sinA-sin²A+1-cosA-sin+sinAcosA)/(1-sinA) (1-cisA)

= (cosA-cos²A+sinA-sin²A+1-cosA-sinA+sinAcosA)/(1-sinA) (1-cosA)

= [-(cos²A+sin²A) +1+sinAcosA]/(1sinA) (1-cosA)

= [-1+1+sinAcosA]/(1-sinA) (1-cosA)

= sinAcosA/(1-sinA) (1-cosA)

=RHS

HOPE THIS WILL HELP YOU...