Math, asked by utkarsharya80, 8 months ago

COSA÷1-tanA+sinA÷1-cotA=sinA+cosA

Answers

Answered by sandy1816
4

Step-by-step explanation:

cosA/1-tanA+sinA/1-cotA

=cos²A/cosA-sinA+sin²A/sinA-cosA

=(cos²A/cosA-sinA)-(sin²A/cosA-sinA)

=cos²A-sin²A/cosA-sinA

=(cosA-sinA)(cosA+sinA)/cosA-sinA

=cosA+sinA

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