Question

cosA = 4/5. in this one of the six trigonometric ratios is given.find the values of the other trigonometric ratios​

Answer 1

Answer:

Hey mate here is your answer.//

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Step-by-step explanation:

Given : CosA = 4/5,

CosA = 4/5  =  Base/Hypotenuse,

In right ∆ ABC ,  

Base (AB) = 4,

Hypotenuse (AC) = 5,

By using Pythagoras theorem,

AC² = AB² + BC²,

5² = 4² + BC²,

25 = 16 + BC²,

BC² = 25 - 16,

BC² = 9,

BC = √9,

BC = 3,

Hence, Perpendicular side (BC)  = 3,

Now, sin A = Perpendicular/ Hypotenuse,

sin A = 3/5,

cosec A = Hypotenuse/Perpendicular,

cosec A = 5/ 3,

sec A = Hypotenuse / Base,

sec A = 5/4,

tan A = Perpendicular /Base,

tan A =  3/4,

cot A = Base/ Perpendicular,

cot A = 4/3.

Hope it helps you.//✔✔✔

Please do mark me as Brainliest.//

Answer 2

yr answer in the attachment................

thank u