Question

cosa=5/√34 find the value of tan A×secA​

Answer 1

cosA = 5/√34

we have to solve tanA.secA

so let's simplify the terms -

tanA = sinA/cosA and secA = 1/cosA

substitution of these values in original equation gives us :-

sinA/cos²A

to find sinA, we can use this identity -

sin²A + cos²A = 1

=> sin²A + 25/34 = 1

=> sin²A = 1 - 25/34 = 9/34

=> sinA = 3/√34

put value of sinA in our equation :-

sinA ÷ cos²A

=> 3/√34 ÷ 25/34

=> 3/√34 × 34/25

=> (3√34)/25

Answer 2

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Hope it helped (◕ᴗ◕✿)