Math, asked by aarya101, 1 year ago

cosA.cos2A.cos4A.cos8A=sin16A/16sinA

Answers

Answered by virendersangwan

RHS
sin16A/16sinA
2sin8Acos8A/16sinA
sin8Acos8A/8sinA
2sin4Acos4Acos8A/8sinA
sin4Acos4Acos8A/4sinA
2sin2Acos2Acos4Acos8A/4sinA
sin2Acos2Acos4Acos8A/2sinA
2sinAcosAcos2Acos4Acos8A/2sinA
cosAcos2Acos4Acos8A

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