Question

cosa+(cosa)^2+(cosa)^3=1 then what will be the minimum value of tana

Answer 1

Answer:

As we know that cos A =1/secA

so by receprocal

cosA =√3/2

cosA=cos 30 degree

A=30

so

tan 30/cos30+ 1+sin30/tan30

1/√3/√3/2+1+1/2/1/√3

by adding you will get 2/3+√3/2

so answer is 4+3√3/6

hope it will help you

Answer 2

Answer:

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