Question

cosA/cosB=sin(C-x)/sin(C+x) then tanx is​

Answer 1

Answer:

Step-by-step explanation:

cosA/cosB=sin(C-x)/sin(C+x)

applying componendo and divendo

cos a+cos b/cos a-cos b=sin c*cos x/cos c*sin x

cos a+cos b/cos a- cos b=tanc/tanx

tanx/tan c=cos a- cos b/cos a+cos b

tanx=cos a-cosb/cos+cos b*tan c

Answer 2

Answer:

please see the attachment