cosA + root3 sinA =root2 then A=
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cosA+√3sinA=√2
divide both sides by 2 we get
1/2cosA+√3/2sinA=√2/2
sin30cosA+cos30sinA=1/√2
sin(30+A)=sin45
30+A=45
A=15
divide both sides by 2 we get
1/2cosA+√3/2sinA=√2/2
sin30cosA+cos30sinA=1/√2
sin(30+A)=sin45
30+A=45
A=15
Rudranarayan1:
but just replace a with tehta. costehta + root 3 sin tehta = root 2 then tetha =
no matter if it is ntse question or not but please follow me
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