Cosa/seca +sins/coseca =sec^2a-tan^2a
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we know , 1+tan^2=sec^2. ,so 1=sec^2A-tan^2A
cosA/(1/cosA)+sinA/(1/sinA)
=cos^2A+sin^2
=1, now
1=sec^2A-tan^2A.....
plzz mark it as a brainliest answer
cosA/(1/cosA)+sinA/(1/sinA)
=cos^2A+sin^2
=1, now
1=sec^2A-tan^2A.....
plzz mark it as a brainliest answer
Bhaavya1:
hey if mine is correct then please mark it as a brainliest answer
Answered by
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Proved...
Please mark it as the Brainliest Answer .....
Please mark it as the Brainliest Answer .....
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I can't understand the last 2 steps
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