Question

cosA - SinA +1 / cosA +SinA -1 =1+ cosA / SinA

Pls helps Guyz !!!! no spam

Answer 1

Step-by-step explanation:

cosA-sinA+1/cosA+sinA-1

devide sinA in both numerator & denominator

cotA-1+cosecA/cotA+1-cosecA

=cosecA+cotA-(cosec²A-cot²A)/ (cotA+1-cosecA)

=cosecA+cotA-(cosecA-cotA)(cosecA+cotA)/(cotA+1-cosecA)

=(cosecA+cotA)(1-cosecA+cotA)/ (cotA+1-cosecA)

=cosecA+cotA

=1/sinA+cosA/sinA

=1+cosA/sinA

thanks sister

Answer 2

Answer:

$\huge{\mathfrak{\underline{\orange{;)AnsWer:-}}}}$

____________

Step by step explanation:-

Picture is attached ; your solution is in that

________________

Identity we used;

(a+b)(a-b)=a^2-b^2

cosecA=1/sinA

cotA=CosA/sinA