Math, asked by dayalupawar6628, 1 year ago

CosA-sinA +1/cosA+sinA-1=secA+tanA

Answers

Answered by sultan85

2

cosA-sinA+1/cosA+sinA-1=secA+tanA

Lhs

cosA-sinA+1/cosA+sinA-1

divided by SinA

cosA/sinA-sinA/sinA+1/sinA

cosA/sinA+sinA/sinA-1/sinA

cotA-1+cosecA/cotA+1-cosecA

cotA+cosecA-1/cotA-cosecA+1

cotA+cosecA-(cosec^2A-cot^2A)/cotA-cosecA+1

cotA+cosecA-(cosecA+cotA)(cosecA-cotA)/cotA-cosecA+1

cotA+cosecA (1-cosecA+cotA)/cotA-cosecA+1

cotA+cosecA (1-cosecA+cotA)/1-cosecA+cotA

cotA+cosecA

hence proof

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