cosA x cosB - sinA x sinB (tanA=1;tanB=sq root 3)
Answers
Answered by
1
tan A=1
sinA/cosA=1
sinA=cosA;------(1)
=tan B=root 3
sinB=cosB.root 3;-----(2)
cosA.cosB - sinA.sinB
=cosA.cosB-cosA.cosB.root 3
sinA/cosA=1
sinA=cosA;------(1)
=tan B=root 3
sinB=cosB.root 3;-----(2)
cosA.cosB - sinA.sinB
=cosA.cosB-cosA.cosB.root 3
RishiReings:
hope it's half right
Answered by
1
Hey dear here is ur answer ✅
It is given that
tanA=1
So A=45°
And tanB=√3
So B=60°
E
We know that it is formula of cos(A+B)
So putting given values and now
=Cos(60°+45°)
=cos105°=√3-1/2 √2
Hope it will help you
It is given that
tanA=1
So A=45°
And tanB=√3
So B=60°
E
We know that it is formula of cos(A+B)
So putting given values and now
=Cos(60°+45°)
=cos105°=√3-1/2 √2
Hope it will help you
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