Math, asked by gunalan9079, 1 year ago

cosec^2 57 - tan^2 33 = ? (a) 0 (b) 1 (c) -1 (d) 2

Answers

Answered by Anonymous
9
Given Equation : Cosec²57 - tan²33

We know that : Cosec²(90-∅) = Sec²∅

•°• Cosec²57 - tan²33

= Cosec²(90-33) - tan²33

= Sec²33 - tan²33

= 1. [ •°• Sec²A - tan²A = 1 ]



Trigonometry Identity Used :

✏ Sec²A - tan²A = 1

✏ Sec²A = 1 + tan² A

✏ tan²A = Sec²A - 1



Trigonometry Ratio Used:

✏ Cosec²(90-∅) = Sec²∅

✏ Sec²(90-∅) = Cosec²∅
Answered by Anonymous
6
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QUESTION :)



cosec^2 57 - tan^2 33 = ? (a) 0 (b) 1 (c) -1 (d) 2


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