cosec^2 57 - tan^2 33 = ? (a) 0 (b) 1 (c) -1 (d) 2
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Answered by
9
Given Equation : Cosec²57 - tan²33
We know that : Cosec²(90-∅) = Sec²∅
•°• Cosec²57 - tan²33
= Cosec²(90-33) - tan²33
= Sec²33 - tan²33
= 1. [ •°• Sec²A - tan²A = 1 ]
Trigonometry Identity Used :
✏ Sec²A - tan²A = 1
✏ Sec²A = 1 + tan² A
✏ tan²A = Sec²A - 1
Trigonometry Ratio Used:
✏ Cosec²(90-∅) = Sec²∅
✏ Sec²(90-∅) = Cosec²∅
We know that : Cosec²(90-∅) = Sec²∅
•°• Cosec²57 - tan²33
= Cosec²(90-33) - tan²33
= Sec²33 - tan²33
= 1. [ •°• Sec²A - tan²A = 1 ]
Trigonometry Identity Used :
✏ Sec²A - tan²A = 1
✏ Sec²A = 1 + tan² A
✏ tan²A = Sec²A - 1
Trigonometry Ratio Used:
✏ Cosec²(90-∅) = Sec²∅
✏ Sec²(90-∅) = Cosec²∅
Answered by
6
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QUESTION :)
cosec^2 57 - tan^2 33 = ? (a) 0 (b) 1 (c) -1 (d) 2
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QUESTION :)
cosec^2 57 - tan^2 33 = ? (a) 0 (b) 1 (c) -1 (d) 2
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