If one zero of polynomial x2+px+9 is twice the other.find p and q
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Let one root of given Polynomial is a then other root is 2a
Now sum of roots = -coefficient of x/coefficient of x
a + 2a = -P
3a = P-----(1)
Again, product of roots = constant/coefficient of x²
a.2a = 9
⇒2a² = 9
⇒ a = ±3/√2
Put a in equation (1),
P = ±9/√2
Now sum of roots = -coefficient of x/coefficient of x
a + 2a = -P
3a = P-----(1)
Again, product of roots = constant/coefficient of x²
a.2a = 9
⇒2a² = 9
⇒ a = ±3/√2
Put a in equation (1),
P = ±9/√2
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