Math, asked by IASaspirant, 11 months ago

cosec ( 2A + 3B ) = √2 and cos ( 2/3A + 4B ) = √3/2 find A and B which are acute angles​

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Answered by saumya5476
5

Step-by-step explanation:

cosec (2A +3B) =cosec 45

on comparing both side

2A + 3B = 45 ..... (i)

Cos (2/3A + 4B) = cos 30

on comparing both side

2/3A + 4B =30 ........ (ii)

by solving equation (i) and (ii)

B = 5

A = 15

Answered by cskooo7
3

Answer:

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