(cosec 40 degree into sin 40 degree)+(cos 40 degree into sec 40 degree)
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6
since ; cosec= 1/sinø and secø=1/cosø
cosec40°. sin40° + cos40°.sec40°
=( 1/sin40° × sin40°) + (cos40° ×1/cos40°)
= 1+1
=2
cosec40°. sin40° + cos40°.sec40°
=( 1/sin40° × sin40°) + (cos40° ×1/cos40°)
= 1+1
=2
menakapal999p9aeix:
cosec/sin = 1 ??? is it ??
Answered by
3
Heya !!
(cosec 40° × sin 40° ) + (cos 40° × sec 40°)
= (1/sin 40° × sin 40°) + ( cos 40° × 1/cos 40°)
= 1 + 1
= 2
Let's take an example, consider a Triangle ABC , right angled at B.
So now ,
sinC = p/h
and
cosec C = h/p
So, they are reciprocal to each other.
(cosec 40° × sin 40° ) + (cos 40° × sec 40°)
= (1/sin 40° × sin 40°) + ( cos 40° × 1/cos 40°)
= 1 + 1
= 2
Let's take an example, consider a Triangle ABC , right angled at B.
So now ,
sinC = p/h
and
cosec C = h/p
So, they are reciprocal to each other.
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