Question

cosec 5o
cose c35 cosecs
Cos 100° + sin 20° + cost
o
Sin 50 sin 35 sin 5​

Answer 1

cos55°=cos(90°-35°)=sin35°

cos70°=cos(90°-20°)=sin20°

tan5°=cot85°tan25°=cot65°

=> 3sin35°/7sin35°=4(sin20°cosec20°)/7(cot85°tan85°cot65°tan65°tan45°)

=> 3/7-4/7=-1/7

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