Math, asked by neha498, 1 year ago

cosec^6= cot^6+ 3 cot^2 cosec ^2 +1

Answers

Answered by AnamSiddiqui28
75


 cosec 6A = cot 6A + 3 cot 2A cosec 2A + 1

Then, we will prove it as :

To Prove:

   cosec 6A = cot 6A + 3 cot 2A cosec 2A + 1

i.e.  cosec 6A – cot 6A – 3 cot 2A cosec 2A = 1

Taking L.H.S. ,

 cosec 6A – cot 6A – 3 cot 2A cosec 2A

= (cosec 2A)3 – (cot 2A)3 – 3 cot 2A cosec2A

= {(cosec 2A – cot 2A) ((cosec 2A)2 + (cot 2A)2 + cosec 2A cot 2A)}

= {1 ((cosec 2A)2 + (cot 2A)2 – 2 cosec 2A  cot 2A + 2 cosec 2A cot 2A + cosec 2A cot 2A)}  – 3 cot 2A cosec 2A

= {(cosec 2A – cot 2A)2 + 3 cosec 2A cot 2A}  – 3 cosec 2A cot 2A

= (cosec 2A – cot 2A)2

= (1)2

=  1

Hence,

   cosec 2A – cot 6A – 3 cot 2A cosec 2A = 1

⇒   cosec 2A = cot 6A + 3 cot 2A cosec 2A + 1


hope answer helpful


Anonymous: awesome speed!!
AnamSiddiqui28: Thanks...
Anonymous: Is it correct??
AnamSiddiqui28: yeSs
Answered by Anonymous
149
Heya mate!!

Your solution is in the attachment.

#Kevin

Hope it helps you :))

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