Math, asked by sherry123456, 1 year ago

cosec^{6} [/tex]A- cot^{6} [/tex]A=3 $cot^{2}$ A× $cosec ^{2} A$ +1

thinkdifferent: Plz write in a proper way

sherry123456: ITS PROPER

thinkdifferent: Cosec^6 ? - cot ^6 ?

sherry123456: COSEC^6ASUBTRACT COT^6

sherry123456: ITS COT^6A

thinkdifferent: Ok

Answers

Answered by thinkdifferent

(Cosec^2A )^3 - (cot^2A)^3 =( cosec^2A - cot^2A )( cosec ^4A + cot^4 A + cosec^2A cot^2A) = 1 + { cosec^4A + cot4A -2 cosec^2A cot ^2 A +2 cosec^2A cot^2A + cosec^2A cot^2A} = 1 + { (cosec^2A - cot^2A ) ^2 + 3 cosec^2A cot ^2A = 1 + 1 + 3 cosec^2Acot^2A = 2 + 3 cosec^2Acot^2A

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