Question

Cosec(67+A) - sec(23-A)

Answer 1

cosec (67+A) –Sec(23–A)


cosec [90–(67+A)]–sec(23–A)

{cosec (90-theta) =sec theta

sec (90-67-A) –sec(23-A)

sec(23-A)–sec (23-A)


=0

Answer 2

Hey There,

Here we are going to use one simple relation:

$cosec\, \theta = \sec (90-\theta)$

So, here, we have:

$cosec \,(67+A) - \sec(23-A) \\ \\ = \sec(90-(67+A)) - \sec(23-A) \\ \\ = \sec(23-A) - \sec(23-A) \\ \\ = 0$

Thus, the answer is 0.


Hope it helps
Purva
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