Question

cosec A+Sin A =26/5Find value of codec A^2 +sinA^2

Answer 1

your problem has corrections cosecA^2+sinA^2 is wrong
cosec A+sinA = 26/5----(1)
square both sides of (1)
(cosecA+sinA)^2=(26/5)^2
cosec^2A+sin^2A+2cosecAsinA= 676/25
cosec^2A+sin^2A+2=676/25
since cosecA= 1/sinA
cosec^2A+sin^2A= 676/25-2

=(676-50)/25
=626/25