(cosec A – sin A) (sec A – cos A) (tan A + cot A) = 1
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Step-by-step explanation:
I solve this question
=(1/sinA-sinA)(1/cosA-cosA)(sinA/cosA+cosA/sinA)
take l.c.m.
you have
1-sin^2A/sinA×1-cos^2A/cosA×sin^2A+cos^2A/cosAsinA
then you know that sin^2A+cos^2A=1
then the last step is that
cos^2A/sinA×sin^2A/cosA×1/cosAsinA
cancelling we have cotA×tanA then this the Identity = 1
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