(cosec A - sinA ) (secA- cosA) = 1/tanA+cotA
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Answer:
LHS =(cosecA-sinA) (secA-cosA)
= (1/sinA-sinA)(1/cosA-cosA)
= (1-sin2A/sinA)(1-cos2A/cosA).
=cos2A/sin2A. * sin2A/cosA
=cosA sinA
RHS = 1/tanAcotA
= 1/sinA/cosA+cosA/sinA
= 1/sin2A+cos2A/cosAsinA
=1/1/cosAsinA
= cosAsinA
therefore, LHS=RHS
Hope it will help u
try to understand it ☺
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