Math, asked by anurudhshukla77, 10 months ago

(cosec A - sinA ) (secA- cosA) = 1/tanA+cotA

Answers

Answered by janhavi38

8

Answer:

LHS =(cosecA-sinA) (secA-cosA)

= (1/sinA-sinA)(1/cosA-cosA)

= (1-sin2A/sinA)(1-cos2A/cosA).

=cos2A/sin2A. * sin2A/cosA

=cosA sinA

RHS = 1/tanAcotA

= 1/sinA/cosA+cosA/sinA

= 1/sin2A+cos2A/cosAsinA

=1/1/cosAsinA

= cosAsinA

therefore, LHS=RHS

Hope it will help u

try to understand it ☺

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