cosec- sin o) (sec o - cos ) (tano
+coto) = 1
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Answered by
6
Answer:
LHS=RHS
Step-by-step explanation:
solve LHS
(1/sin-sin)(1/cos-cos)(tan+1/tan) [{cosec=1/sin}{sec=1/cos}{{cot=1/tan}
(1-sin²/sin)(1-cos²/cos)(tan²+1/tan)
(cos²/sin)(sin²/cos²)(sec²/tan)
(cos/1)(sin/1)(1/cos²×cos/sin)
=1
∴LHS=RHS hence proved
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