Question

(cosec - sin)(sec -cos)( tan + cot)​

Answer 1

Step-by-step explanation:

$(cosec - sin)(sec - cos)(tan + cot) \\ \\ = ( \frac{1 - {sin}^{2} }{sin} )( \frac{1 - {cos}^{2} }{cos} )( \frac{ {sin}^{2} + {cos}^{2} }{sincos} ) \\ \\ = \frac{ {cos}^{2} }{sin} \frac{ {sin}^{2} }{cos} \frac{1}{sincos} \\ \\ = 1$