cosec square thita - sec square thita=cot square thita -tan square thita
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X/acosθ+y/bsinθ=1 and x/asinθ-y/bcosθ=1, prove that x²/a²+y²/b²=2.
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If cosec theta-sin theta =a^3 and sec theta -cos theta = b^3, prove that a^2b^2 (a² +b²)=1
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