Cosec theta =root 2, find the value of
1/ tan A+sin A/1+cos A
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My maths exam is on monday .i will mark your answer barinlist
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excuse me I think it's cosecA not theta because the variables will not change
so cosecA=√2
so A =45°
so 1/ tan45°+sin45°/1+cos45°
1/1+(1/√2)/1+1+(1/√2)
=(√2+2)/+√2+1)
so cosecA=√2
so A =45°
so 1/ tan45°+sin45°/1+cos45°
1/1+(1/√2)/1+1+(1/√2)
=(√2+2)/+√2+1)
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