Question

(cosec theta + sin theta) (cosec theta - sin theta) = (cot^2theta + cos^2 theta)

Answer 1

This can be written as
(cosec²Q-Sin²Q).
Using a²-b²=(a+b)(a-b)
((1+cot²Q)-(1-cos²Q))
(1+cot²Q-1+cos²Q)
(cot²Q-cos²Q)
Hope this helps..

Answer 2

i hope this will help you dear friend