cosec thita addition cot thita equal
then find the cosec thita and cot thita
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cosecΦ + cotΦ = √3 .......i)
cosec^2Φ - cot^2Φ = 1
(cosecΦ + cotΦ)(cosecΦ - cotΦ) = 1
cosecΦ - cotΦ = 1/√3 .....ii)
add i) and ii)
2cosecΦ = 1+1/√3
cosecΦ = √3 + 1/ 2√3
nikki256466:
it is right
Answered by
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Answer:
he----
Step-by-step explanation:
late here place of theta =x.
then. cosec x + cot x=√ 3. .......(1)
but we know that ..
cosec ^2 x - cot ^2 =1.
or.(cosec x +cot x)(cosec x- cot x)=1
so ..
cosec x - cot x = 1/√3. ......(2)
equ. (1). +. equ.(2)....
then we find
2 cosec x = 4/√3 = 4√3/3.
________ ___________
cosec x = 2√3/3.
_______________________
cot x = √{cosec ^2 -1}
= √{ (2√3/3)^2-1}
= √{12/9-1}.
= √3/9
= √1/3.
I hope this is right and helps u.
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