Question

Cosec2o+cosec4o+cosec8o+cosec16o=?

Answer 1

Answer:

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Answer 2

Given cosA x cos2A x cos4A x cos8A = sin16A/16sinA

RHS

sin16A/16sinA

[2sin8A cos 8A]/16sinA

[cos8A(2sin4A cos4A)]/8sinA

[cos8A cos 4A(2 sin 2A cos 2A)]/4sinA

[cos 8A cos 4A cos 2A(sin2A)]/2 sinA

[cos8A cos 4A cos 2A(2sinA cos A)]/2

sin A cos A cos 2A cos 4A cos 8A

Hence RHS=LHS

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