Question

cosec45degree x sin45°​

Answer 1

Answer:

what ........I can't understand

Answer 2

$\mathfrak{\huge \underline{Question:}}$

Cos45°x sin 45°

$\mathfrak{\huge \underline{Answer:}}$

Cos45°= cos(90-45)

Cos45°= sin45°

So, Cos45°x sin 45° = $Cos^2 45° =( \frac{1}{\sqrt{2}})^2 = \frac{1}{2}$

[open your book and see complementary angles]