Question

cosecA =13/10 find all t ratios​

Answer 1

Answer:

cosecA=hypotenuse/perpendicular=13/10

Let, hypotenuse=13k

and, perpendicular=10k, where k is positive.

By pythagoras' theorem, we have

hypotenuse²= perpendicular²+base²

base² = hypotenuse²-perpendicular²

base = √13k-10k

base = √3k

Then,sinA=perpendicular/hypotenuse

=10/13

cosA=base/hypotenuse

=√3/13

tanA=perpendicular/base

=10/√3

secA=hypotenuse/base

=13/√3

cotA=base/perpendicular

=√3/10

Hope it will help u..