Math, asked by sandalricha873, 6 months ago

(cosecA - cotA)^2=1-cosA/1+cosA ​

Answers

Answered by yoyodjmansingh
1

L.H.S (CosecA - CotA)^2

= (1/sinA - CosA/SinA)^2

= ( 1 - cosA/SinA )^2

= ( 1 - CosA)^2/ 1 - cos^2 A

= ( 1 - CosA )^2/(1)^2 - ( cos A )^2

= ( 1 - CosA )^2/ (1+CosA)(1-cosA)

= 1 - CosA/ 1+CosA R.H.S

(Proved)

Answered by sandy1816
0

( {cosecA - cotA})^{2}  \\  \\  = ( { \frac{1 - cosA}{sinA} })^{2}  \\  \\  =  \frac{( {1 - cosA})^{2} }{ {sin}^{2} A}  \\  \\  =  \frac{( {1 - cosA})^{2} }{1 -  {cos}^{2}A }  \\  \\  =  \frac{1  - cosA}{1 + cosA}

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