Question

cosecA+cotA/cosecA-cotA=(cosecA+cotA)2​

Answer 1

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

Answer 2

$\frac{\csc A+\cot A}{\csc A-\cot A}=(csc A+\cot A)^2$ Proved.

Step-by-step explanation:

Consider the provided information.

$\frac{\csc A+\cot A}{\csc A-\cot A}=(csc A+\cot A)^2$

Consider the LHS

$=\frac{\csc A+\cot A}{\csc A-\cot A}$

Rationalize the denominator.

=$\frac{\csc A+\cot A}{\csc A-\cot A}\times\frac{\csc A+\cot A}{\csc A+\cot A}$

$=\frac{(\csc A+\cot A)^2}{\csc^2 A-\cot^2 A}$

Now use the property: $\csc^2\theta-\cot^2\theta=1$

$=\frac{(\csc A+\cot A)^2}{1}$

$=(\csc A+\cot A)^2$

LHS=RHS

Hence, proved

#Learn more

Sin theta upon 1 minus cos theta equals to cosec theta + cot theta prove

https://brainly.in/question/9902906